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7e-8e^2=0
a = -8; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·(-8)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*-8}=\frac{-14}{-16} =7/8 $$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*-8}=\frac{0}{-16} =0 $
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